x+2(x-12)+3(x-6)=126

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Solution for x+2(x-12)+3(x-6)=126 equation: 



x+2(x-12)+3(x-6)=126

We move all terms to the left:

x+2(x-12)+3(x-6)-(126)=0

We multiply parentheses

x+2x+3x-24-18-126=0

We add all the numbers together, and all the variables

6x-168=0

We move all terms containing x to the left, all other terms to the right

6x=168

x=168/6

x=28

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