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x+2(x+10)=9(x+3)+5
We move all terms to the left:
x+2(x+10)-(9(x+3)+5)=0
We multiply parentheses
x+2x-(9(x+3)+5)+20=0
We calculate terms in parentheses: -(9(x+3)+5), so:We add all the numbers together, and all the variables
9(x+3)+5
We multiply parentheses
9x+27+5
We add all the numbers together, and all the variables
9x+32
Back to the equation:
-(9x+32)
3x-(9x+32)+20=0
We get rid of parentheses
3x-9x-32+20=0
We add all the numbers together, and all the variables
-6x-12=0
We move all terms containing x to the left, all other terms to the right
-6x=12
x=12/-6
x=-2
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