x+1=32/x=(1/x)+(x-2)=12+x

Solution for x+1=32/x=(1/x)+(x-2)=12+x equation:

x+1=32/x=(1/x)+(x-2)=12+x

We move all terms to the left:

x+1-(32/x)=0


Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x-(+32/x)+1=0

We get rid of parentheses

x-32/x+1=0

We multiply all the terms by the denominator


x*x+1*x-32=0

We add all the numbers together, and all the variables

x+x*x-32=0

Wy multiply elements

x^2+x-32=0

a = 1; b = 1; c = -32;
Δ = b2-4ac
Δ = 12-4·1·(-32)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{129}}{2*1}=\frac{-1-\sqrt{129}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{129}}{2*1}=\frac{-1+\sqrt{129}}{2}
$