x+1=3(1+x)=2(x-5)

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Solution for x+1=3(1+x)=2(x-5) equation: 



x+1=3(1+x)=2(x-5)

We move all terms to the left:

x+1-(3(1+x))=0

We add all the numbers together, and all the variables

x-(3(x+1))+1=0



We calculate terms in parentheses: -(3(x+1)), so:

3(x+1)

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)



We get rid of parentheses

x-3x-3+1=0

We add all the numbers together, and all the variables

-2x-2=0

We move all terms containing x to the left, all other terms to the right

-2x=2

x=2/-2

x=-1

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