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x+16=x2
We move all terms to the left:
x+16-(x2)=0
We add all the numbers together, and all the variables
-1x^2+x+16=0
a = -1; b = 1; c = +16;
Δ = b2-4ac
Δ = 12-4·(-1)·16
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{65}}{2*-1}=\frac{-1-\sqrt{65}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{65}}{2*-1}=\frac{-1+\sqrt{65}}{-2} $
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