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x+12=2/(5x+3)
We move all terms to the left:
x+12-(2/(5x+3))=0
Domain of the equation: (5x+3))!=0We multiply all the terms by the denominator
x∈R
x*(5x+3))-(2+12*(5x+3))=0
We multiply parentheses
x*(5x+3))-(2+60x+=0
We add all the numbers together, and all the variables
60x+x*(5x+3))-(2=0
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