x+1/x-1=a-b/a+b

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Solution for x+1/x-1=a-b/a+b equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+1/x-1 = a-(b/a)+b // - a-(b/a)+b

b/a-a-b+x+1/x-1 = 0

1*x^1+1*x^-1-1*x^0 = 0

(1*x^2-1*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2-1*x^1+1*x^0) = 0

x^1

x^2-x+1 = 0

x^2-x+1 = 0

DELTA = (-1)^2-(1*1*4)

DELTA = -3

DELTA < 0

x in { } 

x belongs to the empty set

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