x+1/2x+2/3x=x-4

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Solution for x+1/2x+2/3x=x-4 equation:



x+1/2x+2/3x=x-4
We move all terms to the left:
x+1/2x+2/3x-(x-4)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We get rid of parentheses
x+1/2x+2/3x-x+4=0
We calculate fractions
x-x+3x/6x^2+4x/6x^2+4=0
We add all the numbers together, and all the variables
3x/6x^2+4x/6x^2+4=0
We multiply all the terms by the denominator
3x+4x+4*6x^2=0
We add all the numbers together, and all the variables
7x+4*6x^2=0
Wy multiply elements
24x^2+7x=0
a = 24; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·24·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*24}=\frac{-14}{48} =-7/24 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*24}=\frac{0}{48} =0 $

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