x+1-(1-2x)=3+4x-(x-4x)

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Solution for x+1-(1-2x)=3+4x-(x-4x) equation:



x+1-(1-2x)=3+4x-(x-4x)
We move all terms to the left:
x+1-(1-2x)-(3+4x-(x-4x))=0
We add all the numbers together, and all the variables
x-(-2x+1)-(3+4x-(-3x))+1=0
We get rid of parentheses
x+2x-(3+4x-(-3x))-1+1=0
We calculate terms in parentheses: -(3+4x-(-3x)), so:
3+4x-(-3x)
determiningTheFunctionDomain 4x-(-3x)+3
We get rid of parentheses
4x+3x+3
We add all the numbers together, and all the variables
7x+3
Back to the equation:
-(7x+3)
We add all the numbers together, and all the variables
3x-(7x+3)=0
We get rid of parentheses
3x-7x-3=0
We add all the numbers together, and all the variables
-4x-3=0
We move all terms containing x to the left, all other terms to the right
-4x=3
x=3/-4
x=-3/4

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