x+(x-4)+(x-5)=51

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Solution for x+(x-4)+(x-5)=51 equation: 



x+(x-4)+(x-5)=51

We move all terms to the left:

x+(x-4)+(x-5)-(51)=0

We get rid of parentheses

x+x+x-4-5-51=0

We add all the numbers together, and all the variables

3x-60=0

We move all terms containing x to the left, all other terms to the right

3x=60

x=60/3

x=20

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