x+(x+2)+3(x+2)=108

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Solution for x+(x+2)+3(x+2)=108 equation:


Simplifying
x + (x + 2) + 3(x + 2) = 108

Reorder the terms:
x + (2 + x) + 3(x + 2) = 108

Remove parenthesis around (2 + x)
x + 2 + x + 3(x + 2) = 108

Reorder the terms:
x + 2 + x + 3(2 + x) = 108
x + 2 + x + (2 * 3 + x * 3) = 108
x + 2 + x + (6 + 3x) = 108

Reorder the terms:
2 + 6 + x + x + 3x = 108

Combine like terms: 2 + 6 = 8
8 + x + x + 3x = 108

Combine like terms: x + x = 2x
8 + 2x + 3x = 108

Combine like terms: 2x + 3x = 5x
8 + 5x = 108

Solving
8 + 5x = 108

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 5x = 108 + -8

Combine like terms: 8 + -8 = 0
0 + 5x = 108 + -8
5x = 108 + -8

Combine like terms: 108 + -8 = 100
5x = 100

Divide each side by '5'.
x = 20

Simplifying
x = 20

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