x+(x+2)+(x+4)+(x+6)=412

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Solution for x+(x+2)+(x+4)+(x+6)=412 equation: 



x+(x+2)+(x+4)+(x+6)=412

We move all terms to the left:

x+(x+2)+(x+4)+(x+6)-(412)=0

We get rid of parentheses

x+x+x+x+2+4+6-412=0

We add all the numbers together, and all the variables

4x-400=0

We move all terms containing x to the left, all other terms to the right

4x=400

x=400/4

x=100

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