x+(x+2)+(x+4)+(x+6)=152

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Solution for x+(x+2)+(x+4)+(x+6)=152 equation: 



x+(x+2)+(x+4)+(x+6)=152

We move all terms to the left:

x+(x+2)+(x+4)+(x+6)-(152)=0

We get rid of parentheses

x+x+x+x+2+4+6-152=0

We add all the numbers together, and all the variables

4x-140=0

We move all terms containing x to the left, all other terms to the right

4x=140

x=140/4

x=35

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