x+(x+2)+((x+2)+4)=29

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Solution for x+(x+2)+((x+2)+4)=29 equation: 



x+(x+2)+((x+2)+4)=29

We move all terms to the left:

x+(x+2)+((x+2)+4)-(29)=0

We get rid of parentheses

x+x+((x+2)+4)+2-29=0



We calculate terms in parentheses: +((x+2)+4), so:

(x+2)+4

We get rid of parentheses

x+2+4

We add all the numbers together, and all the variables

x+6

Back to the equation:

+(x+6)



We add all the numbers together, and all the variables

2x+(x+6)-27=0

We get rid of parentheses

2x+x+6-27=0

We add all the numbers together, and all the variables

3x-21=0

We move all terms containing x to the left, all other terms to the right

3x=21

x=21/3

x=7

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