x+(x+2)+((2+x)+4)=196

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Solution for x+(x+2)+((2+x)+4)=196 equation: 



x+(x+2)+((2+x)+4)=196

We move all terms to the left:

x+(x+2)+((2+x)+4)-(196)=0

We add all the numbers together, and all the variables

x+(x+2)+((x+2)+4)-196=0

We get rid of parentheses

x+x+((x+2)+4)+2-196=0



We calculate terms in parentheses: +((x+2)+4), so:

(x+2)+4

We get rid of parentheses

x+2+4

We add all the numbers together, and all the variables

x+6

Back to the equation:

+(x+6)



We add all the numbers together, and all the variables

2x+(x+6)-194=0

We get rid of parentheses

2x+x+6-194=0

We add all the numbers together, and all the variables

3x-188=0

We move all terms containing x to the left, all other terms to the right

3x=188

x=188/3

x=62+2/3

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