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x+(x+1)=3(x+1)
We move all terms to the left:
x+(x+1)-(3(x+1))=0
We get rid of parentheses
x+x-(3(x+1))+1=0
We calculate terms in parentheses: -(3(x+1)), so:We add all the numbers together, and all the variables
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
2x-(3x+3)+1=0
We get rid of parentheses
2x-3x-3+1=0
We add all the numbers together, and all the variables
-1x-2=0
We move all terms containing x to the left, all other terms to the right
-x=2
x=2/-1
x=-2
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