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x+(x+1)=193x+(x+1)=193
We move all terms to the left:
x+(x+1)-(193x+(x+1))=0
We get rid of parentheses
x+x-(193x+(x+1))+1=0
We calculate terms in parentheses: -(193x+(x+1)), so:We add all the numbers together, and all the variables
193x+(x+1)
We get rid of parentheses
193x+x+1
We add all the numbers together, and all the variables
194x+1
Back to the equation:
-(194x+1)
2x-(194x+1)+1=0
We get rid of parentheses
2x-194x-1+1=0
We add all the numbers together, and all the variables
-192x=0
x=0/-192
x=0
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