x+(x+1)+15=2x+4(x+1)

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Solution for x+(x+1)+15=2x+4(x+1) equation: 



x+(x+1)+15=2x+4(x+1)

We move all terms to the left:

x+(x+1)+15-(2x+4(x+1))=0

We get rid of parentheses

x+x-(2x+4(x+1))+1+15=0



We calculate terms in parentheses: -(2x+4(x+1)), so:

2x+4(x+1)

We multiply parentheses

2x+4x+4

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We add all the numbers together, and all the variables

2x-(6x+4)+16=0

We get rid of parentheses

2x-6x-4+16=0

We add all the numbers together, and all the variables

-4x+12=0

We move all terms containing x to the left, all other terms to the right

-4x=-12

x=-12/-4

x=+3

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