x+(x+1)+(x+2)=12(x+1)+300

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Solution for x+(x+1)+(x+2)=12(x+1)+300 equation: 



x+(x+1)+(x+2)=12(x+1)+300

We move all terms to the left:

x+(x+1)+(x+2)-(12(x+1)+300)=0

We get rid of parentheses

x+x+x-(12(x+1)+300)+1+2=0



We calculate terms in parentheses: -(12(x+1)+300), so:

12(x+1)+300

We multiply parentheses

12x+12+300

We add all the numbers together, and all the variables

12x+312

Back to the equation:

-(12x+312)



We add all the numbers together, and all the variables

3x-(12x+312)+3=0

We get rid of parentheses

3x-12x-312+3=0

We add all the numbers together, and all the variables

-9x-309=0

We move all terms containing x to the left, all other terms to the right

-9x=309

x=309/-9

x=-34+1/3

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