x+(x+1)+(x+2)-(x+3)=146

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Solution for x+(x+1)+(x+2)-(x+3)=146 equation: 



x+(x+1)+(x+2)-(x+3)=146

We move all terms to the left:

x+(x+1)+(x+2)-(x+3)-(146)=0

We get rid of parentheses

x+x+x-x+1+2-3-146=0

We add all the numbers together, and all the variables

2x-146=0

We move all terms containing x to the left, all other terms to the right

2x=146

x=146/2

x=73

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