x+(6x-5)/9-4=(4x+2)/3

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Solution for x+(6x-5)/9-4=(4x+2)/3 equation: 


x in (-oo:+oo)

(6*x-5)/9+x-4 = (4*x+2)/3 // - (4*x+2)/3

(6*x-5)/9-((4*x+2)/3)+x-4 = 0

(6*x-5)/9+(-1*(4*x+2))/3+x-4 = 0

(3*(6*x-5))/(3*9)+(-1*9*(4*x+2))/(3*9)+(3*9*x)/(3*9)+(-4*3*9)/(3*9) = 0

3*(6*x-5)-1*9*(4*x+2)+3*9*x-4*3*9 = 0

27*x-18*x-108-33 = 0

9*x-108-33 = 0

9*x-141 = 0

(9*x-141)/(3*9) = 0

(9*x-141)/(3*9) = 0 // * 3*9

9*x-141 = 0

9*x-141 = 0 // + 141

9*x = 141 // : 9

x = 141/9

x = 47/3

x = 47/3

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