x+(6x-3)=7-2(x+1)

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Solution for x+(6x-3)=7-2(x+1) equation: 



x+(6x-3)=7-2(x+1)

We move all terms to the left:

x+(6x-3)-(7-2(x+1))=0

We get rid of parentheses

x+6x-(7-2(x+1))-3=0



We calculate terms in parentheses: -(7-2(x+1)), so:

7-2(x+1)

determiningTheFunctionDomain
-2(x+1)+7

We multiply parentheses

-2x-2+7

We add all the numbers together, and all the variables

-2x+5

Back to the equation:

-(-2x+5)



We add all the numbers together, and all the variables

7x-(-2x+5)-3=0

We get rid of parentheses

7x+2x-5-3=0

We add all the numbers together, and all the variables

9x-8=0

We move all terms containing x to the left, all other terms to the right

9x=8

x=8/9

x=8/9

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