x+(3x-16)=228

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Solution for x+(3x-16)=228 equation: 



x+(3x-16)=228

We move all terms to the left:

x+(3x-16)-(228)=0

We get rid of parentheses

x+3x-16-228=0

We add all the numbers together, and all the variables

4x-244=0

We move all terms containing x to the left, all other terms to the right

4x=244

x=244/4

x=61

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