x+(3x-1)+(2x+1)=4(.5x+3)

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Solution for x+(3x-1)+(2x+1)=4(.5x+3) equation: 



x+(3x-1)+(2x+1)=4(.5x+3)

We move all terms to the left:

x+(3x-1)+(2x+1)-(4(.5x+3))=0

We get rid of parentheses

x+3x+2x-(4(.5x+3))-1+1=0



We calculate terms in parentheses: -(4(.5x+3)), so:

4(.5x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

6x-(4x+12)=0

We get rid of parentheses

6x-4x-12=0

We add all the numbers together, and all the variables

2x-12=0

We move all terms containing x to the left, all other terms to the right

2x=12

x=12/2

x=6

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