x+(3x+3)=8+(2x+1)

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Solution for x+(3x+3)=8+(2x+1) equation: 



x+(3x+3)=8+(2x+1)

We move all terms to the left:

x+(3x+3)-(8+(2x+1))=0

We get rid of parentheses

x+3x-(8+(2x+1))+3=0



We calculate terms in parentheses: -(8+(2x+1)), so:

8+(2x+1)

determiningTheFunctionDomain
(2x+1)+8

We get rid of parentheses

2x+1+8

We add all the numbers together, and all the variables

2x+9

Back to the equation:

-(2x+9)



We add all the numbers together, and all the variables

4x-(2x+9)+3=0

We get rid of parentheses

4x-2x-9+3=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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