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x+(2x-10)+(2x-20)+40=360
We move all terms to the left:
x+(2x-10)+(2x-20)+40-(360)=0
We add all the numbers together, and all the variables
x+(2x-10)+(2x-20)-320=0
We get rid of parentheses
x+2x+2x-10-20-320=0
We add all the numbers together, and all the variables
5x-350=0
We move all terms containing x to the left, all other terms to the right
5x=350
x=350/5
x=70
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