x+(2x-1)+2(3-x)=(x-2)+(4x+1)

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Solution for x+(2x-1)+2(3-x)=(x-2)+(4x+1) equation:



x+(2x-1)+2(3-x)=(x-2)+(4x+1)
We move all terms to the left:
x+(2x-1)+2(3-x)-((x-2)+(4x+1))=0
We add all the numbers together, and all the variables
x+(2x-1)+2(-1x+3)-((x-2)+(4x+1))=0
We multiply parentheses
x+(2x-1)-2x-((x-2)+(4x+1))+6=0
We get rid of parentheses
x+2x-2x-((x-2)+(4x+1))-1+6=0
We calculate terms in parentheses: -((x-2)+(4x+1)), so:
(x-2)+(4x+1)
We get rid of parentheses
x+4x-2+1
We add all the numbers together, and all the variables
5x-1
Back to the equation:
-(5x-1)
We add all the numbers together, and all the variables
x-(5x-1)+5=0
We get rid of parentheses
x-5x+1+5=0
We add all the numbers together, and all the variables
-4x+6=0
We move all terms containing x to the left, all other terms to the right
-4x=-6
x=-6/-4
x=1+1/2

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