x+(2x+600)+(3x-800)=19000

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Solution for x+(2x+600)+(3x-800)=19000 equation: 



x+(2x+600)+(3x-800)=19000

We move all terms to the left:

x+(2x+600)+(3x-800)-(19000)=0

We get rid of parentheses

x+2x+3x+600-800-19000=0

We add all the numbers together, and all the variables

6x-19200=0

We move all terms containing x to the left, all other terms to the right

6x=19200

x=19200/6

x=3200

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