x+(2x+40)+(3x-50=15,002

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Solution for x+(2x+40)+(3x-50=15,002 equation: 



x+(2x+40)+(3x-50=15.002

We move all terms to the left:

x+(2x+40)+(3x-50-(15.002)=0

We get rid of parentheses

x+2x+(3x-50-(15.002)+40=0

We add all the numbers together, and all the variables

3x+(3x-50-(15.002)+40=0

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