x+(2x+2)=20+(x+2)

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Solution for x+(2x+2)=20+(x+2) equation: 



x+(2x+2)=20+(x+2)

We move all terms to the left:

x+(2x+2)-(20+(x+2))=0

We get rid of parentheses

x+2x-(20+(x+2))+2=0



We calculate terms in parentheses: -(20+(x+2)), so:

20+(x+2)

determiningTheFunctionDomain
(x+2)+20

We get rid of parentheses

x+2+20

We add all the numbers together, and all the variables

x+22

Back to the equation:

-(x+22)



We add all the numbers together, and all the variables

3x-(x+22)+2=0

We get rid of parentheses

3x-x-22+2=0

We add all the numbers together, and all the variables

2x-20=0

We move all terms containing x to the left, all other terms to the right

2x=20

x=20/2

x=10

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