x+(2x)+(x-10)+(3x-50)=360

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Solution for x+(2x)+(x-10)+(3x-50)=360 equation: 



x+(2x)+(x-10)+(3x-50)=360

We move all terms to the left:

x+(2x)+(x-10)+(3x-50)-(360)=0

We add all the numbers together, and all the variables

3x+(x-10)+(3x-50)-360=0

We get rid of parentheses

3x+x+3x-10-50-360=0

We add all the numbers together, and all the variables

7x-420=0

We move all terms containing x to the left, all other terms to the right

7x=420

x=420/7

x=60

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