x+(12/100)x=19.04

Solution for x+(12/100)x=19.04 equation:

x+(12/100)x=19.04

We move all terms to the left:

x+(12/100)x-(19.04)=0


Domain of the equation: 100)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+(+12/100)x-(19.04)=0

We add all the numbers together, and all the variables

x+(+12/100)x-19.04=0

We multiply parentheses

12x^2+x-19.04=0

a = 12; b = 1; c = -19.04;
Δ = b2-4ac
Δ = 12-4·12·(-19.04)
Δ = 914.92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{914.92}}{2*12}=\frac{-1-\sqrt{914.92}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{914.92}}{2*12}=\frac{-1+\sqrt{914.92}}{24}
$