x+(11/100)x=19.98

Solution for x+(11/100)x=19.98 equation:

x+(11/100)x=19.98

We move all terms to the left:

x+(11/100)x-(19.98)=0


Domain of the equation: 100)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+(+11/100)x-(19.98)=0

We add all the numbers together, and all the variables

x+(+11/100)x-19.98=0

We multiply parentheses

11x^2+x-19.98=0

a = 11; b = 1; c = -19.98;
Δ = b2-4ac
Δ = 12-4·11·(-19.98)
Δ = 880.12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{880.12}}{2*11}=\frac{-1-\sqrt{880.12}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{880.12}}{2*11}=\frac{-1+\sqrt{880.12}}{22}
$