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x+(1/2)x+(2/3)x=30-4
We move all terms to the left:
x+(1/2)x+(2/3)x-(30-4)=0
Domain of the equation: 2)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 3)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x+(+1/2)x+(+2/3)x-26=0
We multiply parentheses
x^2+2x^2+x-26=0
We add all the numbers together, and all the variables
3x^2+x-26=0
a = 3; b = 1; c = -26;
Δ = b2-4ac
Δ = 12-4·3·(-26)
Δ = 313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{313}}{2*3}=\frac{-1-\sqrt{313}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{313}}{2*3}=\frac{-1+\sqrt{313}}{6} $
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