x+((0.25x)/10)=800

Solution for x+((0.25x)/10)=800 equation:

x+((0.25x)/10)=800

We move all terms to the left:

x+((0.25x)/10)-(800)=0

We add all the numbers together, and all the variables

x+((+0.25x)/10)-800=0

We multiply all the terms by the denominator


x*10)+((+0.25x)-800*10)=0

We add all the numbers together, and all the variables

x*10)+((+0.25x)=0

Wy multiply elements

10x^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{20}=0$