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x*x+15x=128
We move all terms to the left:
x*x+15x-(128)=0
We add all the numbers together, and all the variables
15x+x*x-128=0
Wy multiply elements
x^2+15x-128=0
a = 1; b = 15; c = -128;
Δ = b2-4ac
Δ = 152-4·1·(-128)
Δ = 737
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{737}}{2*1}=\frac{-15-\sqrt{737}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{737}}{2*1}=\frac{-15+\sqrt{737}}{2} $
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