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x*2x=500
We move all terms to the left:
x*2x-(500)=0
Wy multiply elements
2x^2-500=0
a = 2; b = 0; c = -500;
Δ = b2-4ac
Δ = 02-4·2·(-500)
Δ = 4000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4000}=\sqrt{400*10}=\sqrt{400}*\sqrt{10}=20\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{10}}{2*2}=\frac{0-20\sqrt{10}}{4} =-\frac{20\sqrt{10}}{4} =-5\sqrt{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{10}}{2*2}=\frac{0+20\sqrt{10}}{4} =\frac{20\sqrt{10}}{4} =5\sqrt{10} $
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