x*1.6x=320

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Solution for x*1.6x=320 equation:



x*1.6x=320
We move all terms to the left:
x*1.6x-(320)=0
Wy multiply elements
x^2-320=0
a = 1; b = 0; c = -320;
Δ = b2-4ac
Δ = 02-4·1·(-320)
Δ = 1280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1280}=\sqrt{256*5}=\sqrt{256}*\sqrt{5}=16\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{5}}{2*1}=\frac{0-16\sqrt{5}}{2} =-\frac{16\sqrt{5}}{2} =-8\sqrt{5} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{5}}{2*1}=\frac{0+16\sqrt{5}}{2} =\frac{16\sqrt{5}}{2} =8\sqrt{5} $

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