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x(x-6)=352
We move all terms to the left:
x(x-6)-(352)=0
We multiply parentheses
x^2-6x-352=0
a = 1; b = -6; c = -352;
Δ = b2-4ac
Δ = -62-4·1·(-352)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-38}{2*1}=\frac{-32}{2} =-16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+38}{2*1}=\frac{44}{2} =22 $
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