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x(x+1)-2651=x+x+1
We move all terms to the left:
x(x+1)-2651-(x+x+1)=0
We add all the numbers together, and all the variables
x(x+1)-(2x+1)-2651=0
We multiply parentheses
x^2+x-(2x+1)-2651=0
We get rid of parentheses
x^2+x-2x-1-2651=0
We add all the numbers together, and all the variables
x^2-1x-2652=0
a = 1; b = -1; c = -2652;
Δ = b2-4ac
Δ = -12-4·1·(-2652)
Δ = 10609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10609}=103$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-103}{2*1}=\frac{-102}{2} =-51 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+103}{2*1}=\frac{104}{2} =52 $
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