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x(x+0.5)=60
We move all terms to the left:
x(x+0.5)-(60)=0
We multiply parentheses
x^2+0.5x-60=0
a = 1; b = 0.5; c = -60;
Δ = b2-4ac
Δ = 0.52-4·1·(-60)
Δ = 240.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.5)-\sqrt{240.25}}{2*1}=\frac{-0.5-\sqrt{240.25}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.5)+\sqrt{240.25}}{2*1}=\frac{-0.5+\sqrt{240.25}}{2} $
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