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x(7/9)=40
We move all terms to the left:
x(7/9)-(40)=0
We add all the numbers together, and all the variables
x(+7/9)-40=0
We multiply parentheses
7x^2-40=0
a = 7; b = 0; c = -40;
Δ = b2-4ac
Δ = 02-4·7·(-40)
Δ = 1120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1120}=\sqrt{16*70}=\sqrt{16}*\sqrt{70}=4\sqrt{70}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{70}}{2*7}=\frac{0-4\sqrt{70}}{14} =-\frac{4\sqrt{70}}{14} =-\frac{2\sqrt{70}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{70}}{2*7}=\frac{0+4\sqrt{70}}{14} =\frac{4\sqrt{70}}{14} =\frac{2\sqrt{70}}{7} $
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