x(x-7)-18x=(x-3)(x+16)

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Solution for x(x-7)-18x=(x-3)(x+16) equation: 



x(x-7)-18x=(x-3)(x+16)

We move all terms to the left:

x(x-7)-18x-((x-3)(x+16))=0

We add all the numbers together, and all the variables

-18x+x(x-7)-((x-3)(x+16))=0

We multiply parentheses

x^2-18x-7x-((x-3)(x+16))=0

We multiply parentheses ..

x^2-((+x^2+16x-3x-48))-18x-7x=0



We calculate terms in parentheses: -((+x^2+16x-3x-48)), so:

(+x^2+16x-3x-48)

We get rid of parentheses

x^2+16x-3x-48

We add all the numbers together, and all the variables

x^2+13x-48

Back to the equation:

-(x^2+13x-48)



We add all the numbers together, and all the variables

x^2-25x-(x^2+13x-48)=0

We get rid of parentheses

x^2-x^2-25x-13x+48=0

We add all the numbers together, and all the variables

-38x+48=0

We move all terms containing x to the left, all other terms to the right

-38x=-48

x=-48/-38

x=1+5/19

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