x(x-5)=x(x+4)-10

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Solution for x(x-5)=x(x+4)-10 equation: 



x(x-5)=x(x+4)-10

We move all terms to the left:

x(x-5)-(x(x+4)-10)=0

We multiply parentheses

x^2-5x-(x(x+4)-10)=0



We calculate terms in parentheses: -(x(x+4)-10), so:

x(x+4)-10

We multiply parentheses

x^2+4x-10

Back to the equation:

-(x^2+4x-10)



We get rid of parentheses

x^2-x^2-5x-4x+10=0

We add all the numbers together, and all the variables

-9x+10=0

We move all terms containing x to the left, all other terms to the right

-9x=-10

x=-10/-9

x=1+1/9

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