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x(x-47)=1704
We move all terms to the left:
x(x-47)-(1704)=0
We multiply parentheses
x^2-47x-1704=0
a = 1; b = -47; c = -1704;
Δ = b2-4ac
Δ = -472-4·1·(-1704)
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9025}=95$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-95}{2*1}=\frac{-48}{2} =-24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+95}{2*1}=\frac{142}{2} =71 $
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