x(x-4)+4(x-4)=0

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Solution for x(x-4)+4(x-4)=0 equation:


Simplifying
x(x + -4) + 4(x + -4) = 0

Reorder the terms:
x(-4 + x) + 4(x + -4) = 0
(-4 * x + x * x) + 4(x + -4) = 0
(-4x + x2) + 4(x + -4) = 0

Reorder the terms:
-4x + x2 + 4(-4 + x) = 0
-4x + x2 + (-4 * 4 + x * 4) = 0
-4x + x2 + (-16 + 4x) = 0

Reorder the terms:
-16 + -4x + 4x + x2 = 0

Combine like terms: -4x + 4x = 0
-16 + 0 + x2 = 0
-16 + x2 = 0

Solving
-16 + x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + x2 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + x2 = 0 + 16
x2 = 0 + 16

Combine like terms: 0 + 16 = 16
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}

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