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x(x-36)=90
We move all terms to the left:
x(x-36)-(90)=0
We multiply parentheses
x^2-36x-90=0
a = 1; b = -36; c = -90;
Δ = b2-4ac
Δ = -362-4·1·(-90)
Δ = 1656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1656}=\sqrt{36*46}=\sqrt{36}*\sqrt{46}=6\sqrt{46}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-6\sqrt{46}}{2*1}=\frac{36-6\sqrt{46}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+6\sqrt{46}}{2*1}=\frac{36+6\sqrt{46}}{2} $
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