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x(x-30)=240
We move all terms to the left:
x(x-30)-(240)=0
We multiply parentheses
x^2-30x-240=0
a = 1; b = -30; c = -240;
Δ = b2-4ac
Δ = -302-4·1·(-240)
Δ = 1860
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1860}=\sqrt{4*465}=\sqrt{4}*\sqrt{465}=2\sqrt{465}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{465}}{2*1}=\frac{30-2\sqrt{465}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{465}}{2*1}=\frac{30+2\sqrt{465}}{2} $
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