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x(x-25)=-150
We move all terms to the left:
x(x-25)-(-150)=0
We add all the numbers together, and all the variables
x(x-25)+150=0
We multiply parentheses
x^2-25x+150=0
a = 1; b = -25; c = +150;
Δ = b2-4ac
Δ = -252-4·1·150
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-5}{2*1}=\frac{20}{2} =10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+5}{2*1}=\frac{30}{2} =15 $
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