x(x-17)-18x=(x-3)(x+6)

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Solution for x(x-17)-18x=(x-3)(x+6) equation: 



x(x-17)-18x=(x-3)(x+6)

We move all terms to the left:

x(x-17)-18x-((x-3)(x+6))=0

We add all the numbers together, and all the variables

-18x+x(x-17)-((x-3)(x+6))=0

We multiply parentheses

x^2-18x-17x-((x-3)(x+6))=0

We multiply parentheses ..

x^2-((+x^2+6x-3x-18))-18x-17x=0



We calculate terms in parentheses: -((+x^2+6x-3x-18)), so:

(+x^2+6x-3x-18)

We get rid of parentheses

x^2+6x-3x-18

We add all the numbers together, and all the variables

x^2+3x-18

Back to the equation:

-(x^2+3x-18)



We add all the numbers together, and all the variables

x^2-35x-(x^2+3x-18)=0

We get rid of parentheses

x^2-x^2-35x-3x+18=0

We add all the numbers together, and all the variables

-38x+18=0

We move all terms containing x to the left, all other terms to the right

-38x=-18

x=-18/-38

x=9/19

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